| Main | Assembly Programming | Input/Output | Memory | Computer Architecture | Advanced Topics |
If we are using autovectored interrupts and a device with priority 3 causes an interrupt, at what address in the Interrupt Vector Table will the M68K find the starting address of the Interrupt Service Routine?
The address is 108 (0x6c)
(3+24)*4 = 108 (0x6C) is the address